Two continuums are present:
(A)-->(B)-->(C)
(X)-->(Y)-->(Z)
One has to choose between the two under standard choice theory.
Both A and X diverge from M.
(M) --> ((A)v(X))
As diverging from M, both the strings A and X have elements of M in them as they are variations of M.
Considering both A and X are variations of M, rejoining A and X through what they have in common is the purest execution of choice.
So where both strings may contain M1 as a common variable this is where the strings are synthesized. This results in a new variation of M where it exists as a variation of itself while still maintaining core components of its identity.
(A) --> ((B)M1) --> (C)
(X) --> ((Y)M1) --> (Z)
(M) --> ((A)v(X)) --> ((B)M1(Y)) --> ((C)&(Z)) --> ((M)M)
So where M diverges the new states can be superpositioned to from a variation of the original string while maintain the identity of the original string.