Philosophy Now Forum

Good proof wtf

let me give you my own theory on this subject: I will explain it succinctly, but i would like to put it in a more mathematical form one day: E(U,S), is the probability that the system U, is in the state S. (we will call it the entropy of the state S of the system U) Most of the time, when a system U...

Scott Mayers, thanks for trying something more clear. But i don’t agree, and it is still not the kind for formalized answer i wanted. (I will let Obvious Leo try to convince you on it.) I still wait for the definition of "probability". I said you i will not go outside of a step by step met...

ok, i got it right this time: P(n) = "9 divide (a^n - b^n), and 9 divide (a^(n-1) - b^(n-1))" if (a, b) are anagrams, then 9 divide (a - b) a^2-b^2=(a + b)(a - b) then 9 divide (a^2-b^2) then p(2) If P(n) , then: 9 divide a^n - b^n and 9 divide a^(n-1) - b^(n-1) a^(n+1)-b^(n+1) = (a^n - b^...

wtf wrote:A quick Google search will show that this author is a well-known crank. Regarding calculus, he clearly has never seen the proper formalization of the concept of a limit. He has an Amazon book if anyone wants to send him money.

This was the very probable.

I don’t worry, it was only to inform you that i saw it, but thank you :) I wrote a rapid python program, and it found no counter example, i will try to find a demonstration with you then. #!/bin/python def get_anagram(x): str_x = str(x).zfill(3) str_ana = str_x[1] + str_x[2] + str_x[0] return int(st...

Yes, i did a mistake on it.

I'm still working on hammering out the complete proof. I was looking over the binomial theorem which suggests this is always true (unproven so far). If we have two anagram numbers, x and y, then: y^2•x - x^2•y is always divisible by 9. Check this out on your calculator. PhilX Yes, i don’t know if y...

Just a note: You should write (21^2)^(1/2) and not (21^2)^1/2, because the '^' has priority otherwise. The problem is not only about the fact that p is a real or a whole number, i can only find counter example when it is not a whole number, but your demonstration is still false otherwise. (even if w...

A universe with a beginning presupposes a creator

Please see what i say about the beginning of the universe in The problem with "nothing"..

The problem with "nothing", is to name it , it give the impression that it is a thing . And i see fallacies on this site because of it. In fact, you could use it only when you have another way to say what you want to say, if you can’t, it mean you are using "nothing" in you sente...

Thanks for your answer Obvious Leo, i also read your philosophical article. I have too much to say to each one. (which each make good points, but also some mistake that make me disagree with it). I will only say that despite what seem to teach science, entropy is neither about complexity, nor order....

.................... The Completed Extended Proof (this post should be read together with the first two posts of this thread) First keep in mind that (x^p)^1/p = x, p not equal to 0. This will help you to understand what follows. The difference between the power of two anagram numbers with p = 0 is...

First, in regards to Rilx, he was wrong on several accounts. First he did the algebra wrong. Then he left out some steps. Then he indicated that an infinity of digits would be involved which isn't true (and I'm going to prove it). To start this off, let's suppose we have these two three-digit numbe...

First, I have to ask you to NOT insult. I don't insult you for your view and this only makes me less concerned to care to deal with you. I have no time now, i will answer tomorrow to the rest of the message, but i wanted to say i don’t want to insult you, and if you felt insulted i am sorry. My goa...